Write a C program to convert a Roman numeral ranging from I to L to its decimal equivalent.
#include <stdio.h>
#include <conio.h>
#include <string.h>
#include <stdlib.h>
void main()
{
char rom[30];
int a[30], l, i, k, dec;
clrscr();
printf("Enter the roman number\n");
scanf("%s", &rom);
l =strlen(rom);
for(i = 0; i < l; i++)
{
switch (rom[i])
{
case 'I': a[i] = 1;
break;
case 'V': a[i] = 5;
break;
case 'X': a[i] = 10;
break;
case 'L': a[i] = 50;
break;
case 'C': a[i] = 100;
break;
case 'D': dec = dec + 500;
break;
case 'M': a[i] = 1000;
break;
default : printf("Invalid choice");
break;
}
}
k = a[l - 1];
for(i = l - 1; i > 0; i--)
{
if(a[i] > a[i - 1])
{
k = k - a[i - 1];
}
if(a[i] <= a[i - 1])
{
k = k + a[i - 1];
}
}
printf("decimal equivalent is %d", k);
getch();
}
OUTPUT:
Enter the roman number
XV
decimal equivalent is 15
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